1/31/2024 0 Comments Decibel logarithmic scale![]() Spread one watt over the entire land area of Germany,Ībout three times over, and still it's intense enoughįor the human ear to hear. This one watt be spread over and still be intense enoughįor the human ear to hear it? What do you think? Football field? I don't know, a city? No, it turns out. How diluted could one watt be spread over? How large of an area could If you have one watt, howīig could you make this area? How, spread out. If you have one watt, how big of an area? A watt isn't really that much. Through the square meter, your ear would still be able What this says is thatĮven if only one trillionth of a joule per second passes This is one trillion ofĪ watt per meter square. Than that, a human ear that's healthy shouldīe able to detect it. ![]() What that means is this is the softest possible sound you can hear. This 10 to the negativeġ2 watts per square meter represents the threshold of human hearing. This part of the equation is my favorite. This gives you an idea of how much energy per second pass throughĪ certain amount of area. How many joulels of sound energy per second pass through the one square meter? That would be the number of watts per meter squared which If you asked how many joules per second pass through that one square meter. The power that passes through that area will be, how many joules? If you figure you how many joules pass through this one square meter. This doesn't have to beĪn actual physical object. Power's in, what? Power measure going to watts. You got your ear and a sound wave, say, is coming toward your ear. What this means, think about it this way. In Physics, intensity is defined to be the power divided by the area. If you didn't multiply byġ0, you'd have the bel scale but this is multiplied by 10. The fact that this is the Deci-bel Scale and Somewhere reader just in volume because we're going to The number of decibels and we abbreviate decibel Logarithm, base 10 of I divided by 10 to the negativeġ2 watts per square meter. This is the scale that we use to figure out the loudness of a sound. This is new to me, so take that into consideration.I'm going to tell you about the Decibel Scale. This says that the sound of the siren has an intensity level that is 100 million times the intensity level of a whisper, given they are both the same distance from the listener.įor each 10 db increase, the intensity level is increased by a factor of 10.ġ0 db increase = 10 * the intensity level.Ģ0 db increase = 10^2 * the intensity level.ģ0 db increase = 10^3 * the intensity level.Ĩ0 db increase = 10^8 * the intensity level. Since the siren is 100 db and the whisper is 20 db, then the siren is 80 db higher than the whisper.ĭivide both sides of this equation by 10 to get: This is presumed to also be at a distance of 30 meters from the source of the whisper. You are given that the decibel level of a whisper is 20 db. The intensity level of the siren is 10 billion times the intensity level of the reference level. This means that the intensity level of the siren is 10^10 times more than the intensity level of the reference level. The intensity level of the signal has increased by a factor of 10^10. The decibel level has increased by 100, since the decibel level of the reference signal is 0. The 1 and the w/900 cancel out and the equation becomes: If the intensity level of the siren is equal to 1 * 10^-2 * w/m^2. When m = 30, the intensity level of the reference becomes: The intensity level of the reference becomes: Io is the intensity level of the reference. You can put this solution on YOUR website!
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